Question

let p(x)=x²+5x-3. chech whether the 1/2 is zero of the polynomial p(x).

Answer 1

no it is not a factor

Step-by-step explanation:

x+1/2=0

x=-1

p(x)=x^2+5x-3

x=-7

But for the perfect factor

It must be 0 at place of -7

Answer 2

Answer:

1 / 2 is not zero of  p ( x ) .

Step-by-step explanation:

Given ;

p ( x ) = x² + 5 x - 3

We have to check that whether 1 / 2 is zeroes of p ( x )  or not .

We have being zeroes remainder should be zero .

Putting 1 / 2 in p ( x )  to check

p ( x ) = x² + 5 x - 3

$\displaystyle{ p(1 /2) = ( 1/2)^2+5(1/2) -3 }\\\\\displaystyle{ p(1 /2) =1/8+5/2-3}\\\\\displaystyle{ p(1 /2) =21/8-3}\\\\\displaystyle{ p(1 /2) =-3/8}$

Since remainder is not equal to zero .

Thus for p ( x)   1 / 2 is not zero of  p ( x )  .

Hence we get answer .