Question

let p(x)=x⁴-4c³+5x²-6x+7 find p(½),p(-⅓), p(-⅔)​

Answer 1

Answer:

Hey !!!! ^_^

Here is your answer

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\begin{gathered}p(x) = {x}^{4} + 4 {x}^{3} + 5 {x}^{2} - 6x + 9 \\ \\ then \: \\ x = - 2 \\ \\ p( - 2) = ({ - 2})^{4} + 4( { - 2})^{3} + 5 {( - 2)}^{2} - 6( - 2) + 9 \\ \\ p( - 2) = 16 - 32 + 20 + 12 + 9 \\ \\ p( - 2) = - 16 + 32 + 9 \\ \\ p( - 2) = 16 + 9 \\ \\ p( - 2) = 25\end{gathered}

p(x)=x

4

+4x

3

+5x

2

−6x+9

then

x=−2

p(−2)=(−2)

4

+4(−2)

3

+5(−2)

2

−6(−2)+9

p(−2)=16−32+20+12+9

p(−2)=−16+32+9

p(−2)=16+9

p(−2)=25

I HOPE IT WILL HELP YOU

Thank you