Question

Let pi be the ith two digit prime number, p0=7,p1=11,p2=13

Answer 1

Answer:

Step-by-step explanation:

Here is the pi for the two digit prime numbers –

P3=17, p4=19, p5=23, p6=29, p7=31, p8=37, p9=41, p10=43, p11=47, p12=53, p13=59, p14=61, p15=67, p16=71, p17=73, p18=79, p19=83, p20=89, p21=97.

Answer 2

Answer:

97.  [Ans]

Step-by-step explanation:

We know that there are finite number of two digit prime numbers. Therefore it is possible to prepare a range followed by an upper limit and a lower limit.

Here p0 refers to the zeroth prime number p1 refers to the first prime number and p2 refers to the second prime number of the series.

So likewise the possible array of 2 digit prime numbers can be:

7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

The value of "i" in here is 21. ("i" denotes the index of last two digit prime number)

Therefore, pi will be 97.