Question

Let PQR be a right triangle in which PQ = 3 cm, QR = 4 cm and Q = 90°. QS is the perpendicular 3 from Q on PR. The circle through Q, R, S is drawn. Construct the tangents from P to this circle.

Answer 1

Answer:

PQ is tangent to Circle

Step-by-step explanation:

PQ = 3 cm, QR = 4 cm

=> PR² = PQ² + QR²

=> PR² = 3² + 4²

=> PR = 5

(1/2) * PQ * QR = (1/2) * PR * QS

=> 3 * 4= 5 * QS

=> QS = 2.4 cm

Now QRS is a right angle triangle

hence Center lies on QR ( Hypotenuse)

Take mid point of QR   as O

OQ = OR = 2 cm

Draw a circle

=> PQ is tangent to Circle

to Draw another tangent take length = 3 cm = pQ

and cut the circle taking P as center

and Draw a line from P to that Point

we will get another Tangent