Let PQR be a right triangle in which PQ = 8cm, QR = 10cm and ∠Q = 90° QS is perpendicular from Q on PR. The circle through Q, R and S is drawn. Construct the tangent from p to the circle
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Answer:
how can we give you a figure this is a very simple answer
Step-by-step explanation:
ok first you construct line PQ(8cm) and make angle Q(90) and then construct line QR 10 cm and make a circle by joining PQR
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