Question

Let PS be the median of the triangle with vertices P(2, 2),Q(6,-1) and (7,3). The equation of the line passing
through (1.-1) and parallel to PS is:


please answer me​

Answer 1

Answer:

2x + 9y + 7 = 0

Step-by-step explanation:

Since S is mid point of Q and R

∴S=(

2

7+6

,

2

3−1

)=(

2

13

,1)

Slope of PS=m=

x

2

−x

1

y

2

−y

1

=

2−

2

13

2−1

=

9

−2

Equation of the line passing through (1,−1) and parllel to PS is

y−(−1)=

9

−2

(x−1)

y+1=

9

−2x+2

⇒9y+9+2x−2=0

⇒2x+9y+7=0