Let R : A →B, where A = { 3,5 } and B = { 7, 11} and R = { ( a, b ) x/3 A x B (a –b) is an odd number}, write the relation R
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A={3,5} B={7,11}
R=(a,b):a∈A,b∈B,a−b is odd.
Let B=7,a=3
b−a=4, which is even.
Each element of B is odd & A also has odd elements.
Hence a−b is never be odd, it will always negetive even no.
Hence R=(a,b)∈ϕ.
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Step-by-step explanation:
A={3,5} B={7,11}
R=(a,b):a∈A,b∈B,a−b is odd.
Let B=7,a=3
b−a=4, which is even.
Each element of B is odd & A also has odd elements.
Hence a−b is never be odd, it will always negetive even no.
Hence R=(a,b)∈ϕ.
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