Question

Let R be a relation defined on Z by a Rb=a>= b. Then Ris​

Answer 1

Answer:

Given that, aRb if a ≥ b

⇒ aRa ⇒ a ≥ a which is true .

Let aRb, a ≥ b, then b ≥ a which is not true, so R is not symmetric .

But aRb and bRc

⇒ a ≥ b and b ≥ c

⇒ a ≥ c

Hence, R is transitive