Let R be a relation on the set of all integers defined as (x, y) R x-y is divisible by 2. Then
write the equivalence class [1].
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R={(x,y):x−yis an integer}
Now, for every x∈Z,(x,x)∈R as x−x=0 is an integer.
∴R is reflexive.
Now, for every x,y∈Z if (x,y)∈R, then x−y is an integer.
⇒−(x−y) is also an integer.
⇒(y−x) is an integer.
∴(y,x)∈R
⇒R is symmetric.
Now,
Let (x,y) and (y,z)∈R, where x,y,z∈Z.
⇒(x−y) and (y−z) are integers.
⇒x−z=(x−y)+(y−z) is an integer.
∴(x,z)∈R
∴R is transitive.
Hence, R is reflexive, symmetric, and transitive. help you this method ok please brilliant Mark
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