Question

Let 'r' be the radius of a circle, h be the perpendicular distance from the centre of the circle to the chord then express length of chord in terms of r and h

Answer 1

OB=r(radius) and OM=h(given)
as we know perpendicular drawn from centre to chord bisects the chord
∴in ΔOMB [by pyth theorem]
OB²=OM²+BM²
r²=h²+BM²
r²-h²=BM²
√(r²-h²)=BM
AB=2BM{perpendicular drawn from centre bisect the chord}
AB=2√(r²-h²)
length of chord will be 2√(r²-h²)