Math, asked by deekshajhansi98, 1 year ago

Let R be the ring of all real valued continuous functions on the closed interval [0, 1]. Let M={f Є R : f(1/3)=0}, show that M is non-empty.​

Answers

Answered by AnkitaSahni
1

We want to show that M is non-empty.

  • R is the ring of all real valued continuous functions on the closed interval [0,1].
  • M = \{f \in R |  f(\frac{1}{3} ) = 0 \} .
  • Consider the function, f(x) = 0 for all x \in [0,1]. Since f is a constant real-valued function defined on the interval [0,1], it is continuous and thus belongs in R.
  • Also, f(\frac{1}{3} ) = 0 . So, f belongs in M.
  • Thus M is non-empty

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