Question

Let R denotes set of all functions from the set A to the set A. If n(A) = p then n(R)is
(a) p!
(b) 2P
(c) pe
(d) 2-1​

Answer 1

Answer:

Pe is the correct answer

Answer 2

Answer:

$p^{p}$ or p^p

Step-by-step explanation:

Concept= Functions

Given= Number of functions in a set relation

To find= Number of functions in the main set

Explanation=

We have been provided with the information that,

There is  R whose set A is mapping from A to A. The functions created is equal to p.

This means that n(A) = p.

Function is mapping of elements from a set of domain to the set of co domain which is called range.

Here the Function maps from A to A with each element.

So if it maps with each element the number of total functions from A to A is p.

Now R contains A.

If A to A to mapping has p number of functions then is R the function can be defined by : p x p x p x p x ........ (p times)

Therefore it is p^p or $p^{p}$.

Therefore n(R)= p^p or $p^{p}$.

#SPJ2