Let R is relation from (11, 12, 13) to {8,10,12)
defined by y = x -3. Then,R' is
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relation is defined from (11,12,13) to (8,10,12) by y=x-3
putting all possible values of x in equation y=x-3
if x=11
y = 11-3 = 8
if x= 12
y= 12-3 =9 (but 9 doesnt exist in y set)
if x= 13
y = 13-3=10
Required relation R = { (11,8),(13,10) }
R' = { (8,11),(10,13) }
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