Question

Let R1 and R2 be the remainders when polynomials x^3 + 2x^2 - 5ax - 7 and x^ 3 + ax^2 - 12 x + 6 are divided by ( x + 1 ) and ( x - 2 ) respectively. If 2R1 + R2 = 6,

Answer 1

Hey dear!!

Here's your answer

When you divide x^3 + 2x^2 - 5ax - 7 by ( x + 1 ), the remainder is 5a - 6

You get this when you put x = -1

And, when you divide x^ 3 + ax^2 - 12 x + 6 by  ( x - 2 ) , the remainder is
4a-10

You get this when you put x = 2

2(5a-6) + 4a-10 = 6
10a + 4a - 12 - 10 = 6

14a = 28

a= 2

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Hope it helps you!!

Sindhu