Let S = {−1, 0, 2, 4, 7}. Find f (S) if
a) f (x) = 1.
b) f (x) = 2x + 1.
c) f (x) = x /5.
d) f (x)=(x2 + 1)/3
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Answered by
24
S = { -1, 0, 2, 4 ,7 }
a) f(S) = { 1} as all elements in the domain map to the same element.
f is a constant function.
b) f(S) = set of all the real values obtained by calculating 2 * x + 1, where
x belongs to S.
= { -1, 1, 5, 9, 15 }
c) f(S) = { -1/5, 0, 2/5 , 4/5 , 7/5 }
d) f(S) = { (1²+1)/3 = 2/3, 1/3, 5/3, 17/3 , 50/3 }
a) f(S) = { 1} as all elements in the domain map to the same element.
f is a constant function.
b) f(S) = set of all the real values obtained by calculating 2 * x + 1, where
x belongs to S.
= { -1, 1, 5, 9, 15 }
c) f(S) = { -1/5, 0, 2/5 , 4/5 , 7/5 }
d) f(S) = { (1²+1)/3 = 2/3, 1/3, 5/3, 17/3 , 50/3 }
Answered by
5
1. f(x) = 1 is a constant function and hence its value will remain the same for all points.
2. f(x) = 2x+1 for S = {-1,0,2,4,7)
f(-1) =2*(-1)+1 = -1
f(0) =2*(0)+1 = 1
f(2) = 2*2+1 = 5
f(4) = 2*4+1 = 9
f(7) = 2*7+1 15
3. f(x)=x/5
f(-1) = -1/5
f(0) = 0/5=0
f(2) = 2/5
f(4) = 4/5
f(7) = 7/5
4. f (x)=(x2 + 1)/3
f(-1) = 2/3
f(0) = 1/3
f(2) = 5/3
f(4) = 17/3
f(7) = 50/3
2. f(x) = 2x+1 for S = {-1,0,2,4,7)
f(-1) =2*(-1)+1 = -1
f(0) =2*(0)+1 = 1
f(2) = 2*2+1 = 5
f(4) = 2*4+1 = 9
f(7) = 2*7+1 15
3. f(x)=x/5
f(-1) = -1/5
f(0) = 0/5=0
f(2) = 2/5
f(4) = 4/5
f(7) = 7/5
4. f (x)=(x2 + 1)/3
f(-1) = 2/3
f(0) = 1/3
f(2) = 5/3
f(4) = 17/3
f(7) = 50/3
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