Let S={1,2,3,4,5,6,7} be a set. Let R be a relation from S to S such that xRy if x
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Step-by-step explanation:
Here, X={1,2,3,4,5,6,7,8,9}
R1={(x,y):x-y is divisible by 3}
As, x-y is divisible by 3.
x-y=3n where n∈N
⇒x=y+3n
y=1,x=4 when n=1
y=1,x=7 when n=2
y=4,x=7 when n=1
y=4,x=1 when n=-1
y=7,x=4 when n=-1
y=7,x=1 when n=-2
∴(x,y)={(1,4),(1,7),(4,7),(4,1),(7,4),(7,1)}
∴(x,y)⊂{1,4,7}
Similarly, (x,y)={(2,5),(2,8),(5,8),(5,2),(8,5),(8,2)}
∴(x,y)⊂{2,5,8}
Similarly, (x,y)={(3,6),(3,9),(6,9),(6,3),(9,6),(9,3)}
∴(x,y)⊂{3,6,9}
∴R1={(x,y):(x,y)⊂{1,4,7}}or{(x,y):(x,y)⊂{2,5,8}}or{(x,y):(x,y)⊂{3,6,9}}
We are given,
∴R2={(x,y):(x,y)⊂{1,4,7}}or{(x,y):(x,y)⊂{2,5,8}}or{(x,y):(x,y)⊂{3,6,9}}
∴R1=R2
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