Question

Let S = {1, 2, 3, ….. , 9}. For k = 1, 2, ….., 5, let Nᴋ be the number of subsets of S, each containing five
elements out of which exactly k are odd. Then N₁ + N₂ + N₃ + N₄ + N₅ =
[A] 210 [B] 252
[C] 125 [D] 126

Answer 1

I Hope that

Option C is a correct answer

ŠüJäŁ ĐôÑgaŘè ✌

Answer 2

Answer:

option c is the correct