Let S = {1, 2, 3}. Determine whether the functions f : S → S defined as
below have inverses. Find f
–1, if it exists.
(a) f = {(1, 1), (2, 2), (3, 3)}
(b) f = {(1, 2), (2, 1), (3, 1)}
(c) f = {(1, 3), (3, 2), (2, 1)}
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Solution
(a) It is easy to see that f is one-one and onto, so that f is invertible with the inverse
f–1 of f given by f
–1 = {(1, 1), (2, 2), (3, 3)} = f.
(b) Since f (2) = f (3) = 1, f is not one-one, so that f is not invertible.
(c) It is easy to see that f is one-one and onto, so that f is invertible with
f–1 = {(3, 1), (2, 3), (1, 2)}.
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