let s=(1m)i+(2m)j+(2m)k and t=(3m)i+(4m)k. the angle between these two vectors is given by:
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Since S. T = |S|. |T| cos theta
Therfore cos theta=(S. T) / |S|. |T|
=(3+8)/3 *5
=11/15
Therfore theta =cos inverse(11/15)
Therfore cos theta=(S. T) / |S|. |T|
=(3+8)/3 *5
=11/15
Therfore theta =cos inverse(11/15)
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