Question

Let's apply, (a+b)² + (a-b)² = 2(a²+b²) or (a+b)² = (a-b)² = 4ab or ab = (a+b/2)² - (a-b/2)² to find 8xy (x²+y²) when (x+y) =9 and (x-y) =5​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

Step-by-step explanation:

Step-by-step explanation: ____________________

Step-by-step explanation: ____________________

Step-by-step explanation: ____________________ We know the algebraic identities:

Step-by-step explanation: ____________________ We know the algebraic identities:

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now,

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now,

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)²

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS Therefore,

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS Therefore,

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS Therefore, (a-b)²=(a+b)²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS Therefore, (a-b)²=(a+b)²-4ab

Step-by-step explanation: ____________________ We know the algebraic identities: 1) (x+y)² = x²+2xy+y² 2)(x-y)² = x²-2xy+y² ____________________ Now, RHS = (a+b)²-4ab = a²+2ab+b²-4ab = a²-2ab+b² = (a-b)² = LHS Therefore, (a-b)²=(a+b)²-4ab •••