Math, asked by avisnakeav121, 7 months ago

Let S be a set of first fourteen natural numbers.
The possible number of pairs (a, b), where a, b belongs to S
and a is not equal to b such that ab leaves remainder 1 when
divided by 15, is

Answers

Answered by sainiandshine

0

Step-by-step explanation:

15divede31 remainder1

Answered by pragati7062

0

Step-by-step explanation:

So divide 15 and 31 you will get 1 as remainder.

31/15=1

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