Question

Let's construct a ∆ABC, so that BC = 5.5cm , ABC=60° and ACB=30°​

Answer 1

First of all ,draw a line segment BC of 5.5 cm.

Then from point B take an angle of 60° and from point C 30° .

Now join the lines and the point of the intersection of these line be A.

Answer 2

Given : ΔABC  BC = 5.5 cm  ∠ABC = 60° , ∠ACB = 30°

To Find : Construct triangle ABC

Solution:

Step 1 : Draw a line segment BC = 5.5 cm

Step 2 : Draw  a ray BX at an angle of 60° at BC using protractor

Step 3 :  Draw an angle of 30° at C on BC using protractor and intersecting ray BX at A

ΔABC is constructed

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