Let's construct a rhombus by 4
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Answers
Step-by-step explanation:
Before talking about the construction of rhombus, let us recall what a quadrilateral is. A quadrilateral is a polygon which has 4 vertices and 4 sides enclosing 4 angles. The sum of its interior angles is 360 degrees, by angle sum property of quadrilateral. A quadrilateral, in general, has sides of different lengths and angles of different measures. However, squares, rectangles, etc. are special types of quadrilaterals with some of their sides and angles being equal. In this article, we will discuss a steps to construct rhombus, where the measurement of its two diagonals is given.
Steps to Construct a Rhombus
A rhombus is a quadrilateral with sides of equal length. Opposite sides are parallel and opposite vertex angles are equal. Let us say, you are required to construct a rhombus PQRS with the lengths of its two diagonals, PR = 6 cm and SQ = 7 cm. We know that the diagonals of a rhombus bisect each other at 90 degrees. Hence, we do not require any other dimension for the construction of rhombus. The steps are:
Draw a vertical line segment PR of length 6 cm.
Construction of Rhombus-Step 1
Take the compass of any radius and from the point P, mark an arc towards the left and the other towards the right of PR. Repeat the same from point R without changing the compass radius.
Construction of Rhombus-Step 2
The other diagonal measures 7 cm. Thus, draw a line joining the two points where the arc intersected each other in such a way that OS = OQ = 7/2 = 3.5 cm
Construction of Rhombus-Step 3
Join the point P with Q, Q with R, R with S and S with P.
Construction of Rhombus-Step 4
PQRS is the required rhombus with the diagonals of lengths 6 cm and 7 cm. Note that O is the mid-point of the two diagonals and ∠POQ = ∠QOR = ∠ROS = ∠SOP = 90 degrees.