Question

Let's do Rationalisation of numerators:
1). 1 upon 3+√5 =
2).1 upon 3-√2 =​

Answer 1

Step-by-step explanation:

Rationalise the denominator of each of the following (i-vii):

(i)

3

√

5

(ii)

3

2

√

5

(iii)

1

√

12

(iv)

√

2

√

5

(v)

√

3

+1

√

2

(vi)

√

2

+

√

5

3

(vii)

3

√

2

√

5

Answer 2

(1)

$\frac{1}{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } \\ \\ = > \frac{3 - \sqrt{5} }{ {(3)}^{2} - {( \sqrt{5}) }^{2} } \\ \\ = > \frac{3 - \sqrt{5} }{9 - 5} = \frac{3 - \sqrt{5} }{4}$

(2)

$\frac{1}{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ \\ = > \frac{3 + \sqrt{2} }{ {(3)}^{2} - {( \sqrt{2}) }^{2} } \\ \\ = > \frac{3 + \sqrt{2} }{9 - 4} = = \frac{3 + \sqrt{2} }{5}$