Question

Let's factorise:
64ax square - 49s(x - 2y) hole square​

Answer 1

Answer:

Answer:

a (15x - 14y) (x + 14y)

Step-by-step explanation:

I understand that this expression needs to be factorize. Considering it, the solution is given below. Hope it helps

          64ax² - 49a(x-2y)²

Taking a common from both terms

         = a [ 64x² - 49(x-2y)² ]

         = a [ ( 8x )² - { 7( x - 2y )}² ]

Applying a² - b² = (a + b) (a - b), where a = (8x) and b = 7(x-2y)

         = a [ (8x + 7( x - 2y ) ] [ 8x - 7 ( x - 2y ) ]

         = a (8x + 7x - 14y)(8x - 7x + 14y)

        = a (15x - 14y) (x + 14y)