Question

Let's find G.C.D 4a²b²,20ab²

Answer 1

Answer:

4a2b2, 20ab2

Factors of 4a2b2=4×a×a×b×b

Factors of 20ab2=4×5×a×b×b

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

∴ The GCD of 4a2b2, 20ab2 is 4ab2