Let's find H.C.F. and L.C.M. of the following numbers.by short division methods (d) 28, 49, 70
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H.C.F = 7 , L.C.M. = 980
EXPLANATION ( HCF )
For H.C.F. first we should find the product of the smallest power of each prime factor in the numbers.
SO, BY PRIME FACTORISATION
28 = 2 × 2 × 7 = 2^2 × 7 (^means square)
49 = 7 × 7 = 7^2
70 = 2 × 5 × 7
H.C.F( 28, 49, 70 ) = 7
L.C.M.
For L.C.M. we need to take the product of the greatest power of each prime factor involved in the numbers. So,
L.C.M(28, 49, 70) = 7^2 × 2^ 2 × 5
= 280
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