Let's find out the heat developed in 3 minutes by a device of resistance 920 ohm working under 230 V.
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Answered by
22
Answer:
H=I^2RT
Explanation:
Heat developed =I^2RT
here R=920 ohm and t=3 minutes=3*60=180 seconds
I=V/R=230/920=0.25
H=0.25*0.25*920*180=10,350 joule
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Answer:
above answer is correct
Explanation:
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