Question

let's go be the centre of a circle ab is a diameter then prove that ACB = 90​

Answer 1

THERE IS A THEOREM THAT

THE ANGLE WHICH IS FORMED AT THE CENTRE OF THE CIRCLE, IS GOING TO BE DOUBLE THEN THE ANGLE AT ANY POINT ON REMAINING CIRCLE

DIAMETER FORMS ANGLE OF 180 AT THE CENTRE OF THE CIRCLE

THEN THE ANGLE WHICH WILL BE FORMED ON THE REMAINING CIRCLE WILL BE HALF OF 180

WHICH IS EQUAL TO 90

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