Question

Let s- long 2(root 7 + root 5) then find the value of log 2(root 7- root 50

Answer 1

Given :   log₂(√7  + √5)   =  S

To find :  log₂(√7  - √5   )

Solution:

log₂(√7  + √5)   =  S

√7  - √5  

= √7  - √5      * (√7  + √5) / (√7  + √5)

= (7 - 5) /(√7  + √5)

= 2/(√7  + √5)

log₂(√7  - √5   )  =  log₂(2/(√7  + √5))

using log (a/b) = log a - log b

= log₂ 2  - log₂ (√7  + √5)

using logₐa = 1   &  log₂ (√7  + √5) = S

= 1  -  S

log₂(√7  - √5   ) = 1 - log₂(√7  + √5)

log₂(√7  - √5   )  = 1  -  S

Learn more:

Solve log base 2x-1 of ( x^4+2)/(2x+1) = 1

https://brainly.in/question/17481275

(Log(base 2) 10).(log(base2) 80)-(log(base2) 5).(log(base2) 160)

https://brainly.in/question/9807694

if log 8=0.9030 and log 9=0.9542 then the value of log 512 to the ...

https://brainly.in/question/9457543