Question

Let's say 4 kg cart experiences a 6 N force to the right, a 39 N force of gravity, a 39 N normal force, a 12 N force to the left, and a 18 N force to the right.
What is the acceleration of the object?

A.) 12 m/s^2
B.) 0 m/s^2
C.) 4 m/s^2
D.) 3 m/s^2

Answer 1

Answer:

D.) 3m/s^2

Explanation:

Summation of all forces acting on a cart:

Fnet = 6N + 39N -39N -12N +18N

Fnet = 12N to the right.

So we know that:

$f = ma$

Putting values of F and m.

$12 = 4a \\ so \\ a = 3 \frac{m}{ {s}^{2} }$