Question

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Numericals

1. A person observes smoke from a gun 1.4 seconds before he hears the bang. If the gun is 476 m away from the person. Find the speed of sound.

2. Calculate the wavelength and time period of tuning fork of frequency 512hz which is set to vibrate. velocity of sound in air is 320 m/s.

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Answer 1

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Answer 1 -

Time taken by the sound to reach the ear=1.4 sec

Distance travelled by the sound wave=476 m

Speed of sound=distance/time

=4760/14

=340m/s



Answer 2 -

F = 512hz
c=320m/s
λ=?

λ=c/v
  =320/512
  = 0.625 m

Wavelength = 0.625 m

T=1/f
   =1/512
   =0.0019 or 0.002 s

Where f and v=frequency,T = time period , c=Speed of light and λ=Wavelength(lambda).

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Answer 2

1 ). Speed = distance /time

Time given = 1.4 secs

Distance given = 476 m

Speed, s = 476 / 1.4 = 340 m / s

______________________________

2 ). Frequency of tuning fork = 512 hz

Velocity of sound in air = 320 m / s

Frequency = Speed / Wavelength

512 = 320 / wavelength

Wavelength = 320 / 512 = 0.625 m

Time period = 1/ frequency

T = 1 / 512

T = 0.00195 or 1.95 × 10^3 / s