Question

Let's simplify: (a-b)+(b-c)+(c-a)​

Answer 1

(a-b)+(b-c)+(c-a)

a-b+b-c+c-a

a-a+b-b-c+c

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hope it helps you...☜ (↼_↼)

Answer 2

Given,

(a-b)+(b-c)+(c-a)

To find,

The simplified value of (a-b)+(b-c)+(c-a).

Solution,

The simplified value of (a-b)+(b-c)+(c-a) is 0.

We can easily solve this problem by following the given steps.

We know that only the numbers with the same variables can be added or subtracted. For example, 5a can only be added to 6a to give 11a but it can not be added to 5c because the addition will be 5a+5c.

According to the question,

(a-b)+(b-c)+(c-a)

a-b+b-c+c-a ( Removing the brackets)

a-c+c-a (b will get subtracted from b)

a-a ( c will get subtracted from c)

0

Hence, the value is 0.

(In this case, we have one positive variable and one negative variable of a, b and c. So, each one will be subtracted and give the value to be 0.)