Question

Let S = sin √2 - sin √3 and C = cos √2 -cos √3 then which one of the following is correct?
(A) S > 0 and C> 0 (B) S > 0 and C<0 (C) S< 0 and C> 0 (D) S < 0 and C < 0
0
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Answer 1

Answer:

Answer of this question is (B)

Answer 2

Answer:

(C)

Step-by-step explanation:

Let us consider an example first

We know that if-:

x = Sin θ - Sin μ (and θ>μ)

then x > 0

therefore,

S = Sin√2 -Sin√3

WILL BE LESS THAN ZERO

AS (√3 > √2)

THEREFORE, S<0

Now let us consider another example

y = cos θ - cos μ

It will be greater than zero if (θ<μ)

Therefore,

C = Cos√2 - Cos√3

WILL BE GREATER THAN ZERO

AS √2 < √3

HENCE FINALLY,

S<0 & C>0

So, (C) is the answer