Let's solve thisA can finish the work in 16 days while B can finish the work in 8 days.After A started the work alone,B joined him after 4 days.Find out the total time taken to finish the work.
Answers
Answer:
8 days..
Step-by-step explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)
A's 2 day work = 2x(1/16) =1/8
Remaining work = 1–1/8 =7/8
( Total work is always presumed to be 1 in all such cases )
Now this remaining work will be done by A and B together .
(A+B)'s 1 day work = (1/16) + (1/12) = 7/48
A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days
Total time taken = 6+2 = 8 days
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Answer:
Let whole work be W.
Work done by A in one day = W/16
Work is done by B in one day = W/12
A worked for 2 days=2×4/16
=W/8
A and B worked for x days(let)
w/8+x(w/16+w/12)=w
x×7/48=7/8
⇒x=6 days.
Hence, the answer is 6 days.