Question

Let's try this problem, Q# if two objects having same mass are put at a distance of 1 meter and force of attraction between them is, 50newton, if separation between them becomes four time then what is the value of force of attraction between them​

Answer 1

Answer:

3.125N

Explanation:

m1=m2

F=Gm1m2/r^2

when masses are same

F=Gm^2/r^2

when r=1m

50=Gm^2/1=50=Gm^2..........(1

when r=4×1=4m

F2=Gm^2/16

on comparing

F2/F1=Gm^2/16/Gm^2

F2/F1=1/16

16F2=F1

F2=F1/16

F2=50/16=3.125N