Question

let sec 2A=cosec 3A then cot 5A=.........

Answer 1

Given info : A trigonometric equation is given by, sec2A = cosec3A

To find : the value of cot5A

Solution : We know, cosec(π/2 - x) = sec x

so, sec2A = cosec(π/2 - 2A) ......(1)

here, sec2A = cosec3A

From equation (1) we get,

⇒cosec(π/2 - 2A) = cosec3A

⇒π/2 - 2A = 3A

⇒π/2 = 2A + 3A = 5A

⇒5A = π/2

taking cot both sides

⇒cot5A = cot(π/2) = 0

Therefore the value of cot5A equals to zero.

Answer 2

Answer:-

Given info :

A trigonometric equation is given by, sec2A = cosec3A

To find :

the value of cot5A

Solution :

We know, cosec(π/2 - x) = sec x

so,

sec2A = cosec(π/2 - 2A) ......(1)

here, sec2A = cosec3A

From equation (1) we get,

⇒cosec(π/2 - 2A) = cosec3A

⇒π/2 - 2A = 3A

⇒π/2 = 2A + 3A = 5A

⇒5A = π/2

taking cot both sides

⇒cot5A = cot(π/2) = 0

Therefore the value of cot5A equals to zero.

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