( let singularity means 0+ ifinite)
(and let infinite means 0.11×0.11^2)
and let zero means time
and let time means (((infinite×0.1883))
then solver 0÷ singularity.
give me answer
if you give me wrong one I I'll report that
Answers
Explanation:
If the missed value is not 00, or if there is no missed value, then 1f1f will have a sequence of poles that converges to z0z0, and hence the singularity at z0z0 will not be isolated. So, thinking of 1f1f as a holomorphic function on its largest possible domain (which will omit some sequence of points converging to z0z0), the singularity at z0z0 is technically unclassifiable.
On the other hand, even in this case you can regard 1f1f as a meromorphic function from Ω∖{z0}Ω∖{z0} to the extended complex plane C^C^, and when considered as such it will have an essential singularity at z0z0. This is a natural enough thing to do that I suspect most people would be happy just saying "1f1f has an essential singularity at z0z0."
Answer:
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