let t be a number when it divided by 11,13and 15 leaves a remainder in the sets (7,8,9),(1,2,3)&(4,5,6) respectively.Find the sum of the squares of the digits of t.
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et's denote the set of required numbers by x. Let a, b & c be whole numbers.
x mod 11 = 1 so x = 11a + 1.
x mod 13 = (11a+1) mod 13 = 2.
11a mod 13 = 1 = 66 mod 13
a mod 13 = 6 mod 13 = 6.
So, a = 13b + 6.
So, x = 143b + 67.
x mod 15 =(143b+67) mod 15=3.
143b mod 15 = -64 mod 15.
143b mod 15 = 11 = 1001mod15
b mod 15 = 7 mod 15 = 7.
b = 15c + 7.
So, x = 2145c + 1068.
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