Question

Let T, be the phe term of an A.P, whose first term is 'a' and common difference is 'd' It for some positive integers 1 T n and then a-d=​

Answer 1

Answer:

Let T1 = a, common difference = d

Tm => a+(m-1)d = 1/n…(i)

Tn => a+(n-1)d = 1/m…(ii)

(i) – (ii)

[(m-1)-(n-1)]d = (1/n)-(1/m)

(m-n)d = (m-n)/mn

d = 1/mn

Substitute d in (i)

a+(m-1)(1/mn) = 1/n

a+(m/mn)-1/mn = 1/n

a+(1/n)-1/mn = 1/n

a = 1/mn

a-d = (1/mn)-(1/mn) = 0

Hence option (2) is the answer.