Math, asked by montulal001, 3 days ago

Let T: R3 → R2 be a linear transformation defined by T(x,y,z) = (3x + 2y – 4z, x - 5y + 3z). Find the matrix of T relative to the basis (1,1,1),(1,1,0),(1,0,0) of R3 and (1,3), (2,5) of R2

Answers

Answered by chaitaliganguly207
0

Answer:

y = c

1

v

1

+ c

2

v

2

+ ... + c

n

v

n

for some unique bi

’s and c

i

’s in . Then, by definition of T, we have

T(x) = b1

w1

+ b2

w2

+ ... + bn

wn

T(y) = c

1

w1

+ c

2

w2

+ ... + c

n

wn

 T(x) + T(y) = (b1

w1

+ b2

w2

+ ... + bn

wn

) + (c

1

w1

+ c

2

w2

+ ... + c

n

wn

)

= (b1

+ c

1

)w1

+ (b2

+ c

2

)w2

+ ... + (bn

+ c

n

)wn

However, x + y = (b1

v

1

+ b2

v

2

+ ... + bn

v

n

) + (c

1

v

1

+ c

2

v

2

+ ... + c

n

v

n

)

= (b1

+ c

1

)v

1

+ (b2

+ c

2

)v

2

+ ... + (bn

+ c

n

)v

n

 T(x + y) = (b1

+ c

1

)w1

+ (b2

+ c

2

)w2

+ ... + (bn

+ c

n

)wn

,

again by definition of T. Hence, T(x + y) = T(x) + T(y). Next, for any scalar c ,

c x = c(b1

v

1

+ b2

v

2

+ ... + bn

v

n

) = (cb1

)v

1

+ (cb2

) v

2

+ ... + (cbn

)v

n

 T(cx) = (cb1

)w1

+ (cb2

)w2

+ ... + (cbn

)wn

= c(b1

w1

) + c(b2

w2

) + ... +c(bn

wn

)

= c(b1

w1

+ b2

w2

+ ... + bn

wn

)

= cT(x)

Hence T is a linear transformation.

To prove the uniqueness, let L : V  W be another linear transformation satisfying

L(v

1

) = w1

, L(v

2

) = w2

, ..., L(v

n

) = wn

If v  V, then v = a1

v

1

+ a2

v

2

+ ... + an

v

n

, for unique scalars a1

, a2

, ..., an  . But then

L(v) = L(a1

v

1

+ a2

v

2

+ ... + an

v

n

)

= a1 L(v

1

) + a2 L(v

2

) + ... + an

L(v

n

) ( L is a L.T.)

= a1

w1

+ a2

w2

+ ... + an

wn

= T(v)

 L = T and hence T is uniquely determined.

EXAMPLE 14 Suppose L : 

3  

2

is a linear transformation with

L([1, –1, 0]) = [2, 1], L([0, 1, –1]) = [–1, 3] and L([0, 1, 0]) = [0, 1].

Find L([–1, 1, 2]). Also, give a formula for L([x, y, z]), for any [x, y, z]  

3

.

[Delhi Univ. GE-2, 2017]

SOLUTION To find L([–1, 1, 2]), we need to express the vector v = [–1, 1, 2] as a linear

combination of vectors v

1

= [1, –1, 0], v

2

= [0, 1, –1] and v

3

= [0, 1, 0]. That is, we need to find

constants a1

, a2

and a3

such that

v = a1 v

1

+ a2 v

2

+ a3 v

3

,

which leads to the linear system whose augmented matr

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