Question

Let $-\frac{\pi}{6} \ \textless \ \theta \ \textless \ -\frac{\pi}{12}$. Suppose α₁ and B₁ are the roots of the equation x² – 2x secα + 1 = 0 and α₂ and β₂ are the roots of the equation x² + 2x tanθ – 1 = 0. If α₁ > β₁ and α₂ > β₂, then α₁ + β₂ equals
(a) 2 (sec θ – tan θ)
(b) 2 sec θ
(c) –2 tan θ
(d) 0

Answer 1

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