Question

Let the area of cross section at the end X of a U tube filled with a liquid be 0.05m2 and that at the end Y be 0.6m2 .If a force of 120N is applied at the end X, what will be the force experienced at the end Y ?​

Answer 1

Answer:

1440 N

check this pic

hope it helps

Answer 2

Answer: 1440 N

Explanation: According to the question,

As let the area of the cross-section at the end X of a U tube filled with a liquid be $0.05m^{2}$ and that at the end Y be$0.6 m^{2}$ .

If a force of 120 N is applied at the end X,

As the $F_{1}=120 N$

$F_{2} =?$

$A_{1} =0.05 m^{2}$

$A_{2} =0.6m^{2}$

As we know $F_{2}=[\frac{A_{2} }{A_{1} }]F_{1}$

so, now by

$F_{2} =[\frac{0.6}{0.05}]120\\F_{2} =12*120\\F_{2} =1440N$

Hence, the force experienced at the end Y is 1440 N.

#SPJ3