let the base of an isosceles triangle be 8 cm and each of the equal sides be 5 cm find its height ?bumper question
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formula to find height of an isosceles triangle is=2xK/base...where k is an equal side
so...................putting values
2xk/base
=2x5/base
=10/8
=1.25 Ans
so...................putting values
2xk/base
=2x5/base
=10/8
=1.25 Ans
a1akul:
wrong answer
Answered by
2
on dividing the base in 2 equal parts we get 8/2 =4 so now the base is 4cm+4cm.
since the 2 equal sides are of 5cm each so on considering half of the triangle we have the base as 4cm, hypotenuse as 5 cm and perpendicular we have to calculate so on following pythagoras theorem we have 5*5=perpendicular *perpendicular+4*4
=> 25=x*x + 16
=>25-16=x*x
=>9=x*x
=>x=√9=3cm.
since the 2 equal sides are of 5cm each so on considering half of the triangle we have the base as 4cm, hypotenuse as 5 cm and perpendicular we have to calculate so on following pythagoras theorem we have 5*5=perpendicular *perpendicular+4*4
=> 25=x*x + 16
=>25-16=x*x
=>9=x*x
=>x=√9=3cm.
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