Let the curve C be the mirror image of the parabola y² = 4x with respect to the line x + y + 4 = 0. If A and B
are the points of intersection of C with the line y = -5, then the distance between A and B is
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Let P(x,y) be the required point on the parabola which is nearest to the focus.
Then D= √(x−a) 2 +y 2
Now y ² =4ax
So, D=√ (x−a) 2 +4ax
D=√(x+a) 2
D=(x+a)
Now, the distance will be shortest when x=0.
Step-by-step explanation:
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