Math, asked by vikashku90, 7 months ago

Let the density function of a random variable X be given by
X +1
fx(x) = -1<x<1
2
Then, the form of the density function of W = X’is,
1
a)
0< W<1
VW
VW
b)
-1<ws1
VW
VW
1
c)
-1<w1
2. W
1
d)
0<w<1
2.vw​

Answers

Answered by KirtiSanom
8

Answer:

If secA-tanA=0.5 and 0<A<90

then find the value of secA? po

Step-by-step explanation:

Let the density function of a random variable X be given by

X +1

fx(x) = -1<x<1

2

Then, the form of the density function of W = X’is,

1

a)

0< W<1

VW

VW

b)

-1<ws1

VW

VW

1

c)

-1<w1

2. W

1

d)

0<w<1

2.vw

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