Question

Let the distance between the plane
3x + 4y + 5z + g = 0 and
3x + 4y + 5z -cz = 0
is 2√2, where c,,c belongsW, then number of
possible ordered pari(s) of(,c1,c2) is taken

as M. Then M/7


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Answer 1

Answer:

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3x+4y+5z+g-(3x+4y+5z-cz)

g+cz=0

g=-cz