Question

let the equation ax2+2hxy+by=0 reprent a pair of straight lines.then the angle tita between the line given by cos ​

Answer 1

Answer:

Step-by-step explanation:

Equation of bisectors of angle between the pair of straight line

ax^ 2 +2hxy+by^ 2  =0 is given by  

x^2 -y^2/  a−b  =  xy/h

⇒hx^2  −(a−b)xy−hy  ^2  =0

Here coefficient of x^  2 + coefficient of y^2  =h+(−h)=0

∴ above equation represent the pair of ⊥er lines