let the equation ax2+2hxy+by=0 reprent a pair of straight lines.then the angle tita between the line given by cos
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Step-by-step explanation:
Equation of bisectors of angle between the pair of straight line
ax^ 2 +2hxy+by^ 2 =0 is given by
x^2 -y^2/ a−b = xy/h
⇒hx^2 −(a−b)xy−hy ^2 =0
Here coefficient of x^ 2 + coefficient of y^2 =h+(−h)=0
∴ above equation represent the pair of ⊥er lines
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