Question

Let the function f:R⇒R be defined by f(x)=x²,

find:

i:f^-1,

ii:f^-1(-4)

Any mod answer this questions please no spams

Answer 1

Answer:

If f : A → B is such that y ∈ B, then

f−1

{ y }={x ∈ A: f (x) = y}.

In other words, f -1{ y} is the set of pre - images of y.

Let

f−1

{17} = x .

Then, f (x) =17 .

⇒ x2 +1 = 17

⇒ x2 = 17 -1 = 16

⇒ x = ± 4

∴

f−1

{17} = { -4,4}

Again,

let

f−1

{ -3} = x .

Then, f (x) =-3

⇒ x2 + 1 = -3

⇒ x2 =- 3 - 1 = -4

⇒

x=−4

Clearly, no soluti on is available in R.

So

f−1

{- 3} = Φ .

Step-by-step explanation:

Please thanks my this answer

Answer 2

Answer:

answer for the given problem is given