Question

Let the initial velocity of the particle is 5 m/s. It is accelerating at an acceleration of
1m/s
2
Its finalvelocity is 10 m/s. Then what is the distance traveled by the particle?

Answer 1

solution:

initial velocity (u) = 5m/s

final velocity (v) = 10m/s

acceleration (a) = 1m/s²

distance (s) = ?

using the 3rd equation of motion..

2as=v²-u²

2×1×s=10²-5²

2s=100-25

s=75/2=37.5m

Answer 2

these is attachment to your question

thanks freind

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